To find if a given number is a perfect cube or not.

import java.io.*;

class cube{

    public static void main(String args[])throws IOException

    {

        BufferedReader input=new BufferedReader(new InputStreamReader(System.in));

        System.out.println("ENTER A NUMBER");

        int n=Integer.parseInt(input.readLine());

        int found=0;

        for(int i=2;i<=(n/2);i++)

        {

            if(n%i==0)

            {

                if((i*i*i)==n)

                found=1;

            }

        }

        if(found==1)

            System.out.println("Perfect Cube");

        else

            System.out.println("Not A perfect cube");

       

    }

}